HARDY WEINBERG PROBLEM

In a population of 1,000 individuals, 44% of the population show the recessive trait.How many individuals would you expect for each of the three possible traits?

STEPS

1.Find the given allele. q2=44%  (homozygous recessive individual)

2.Convert percentage into a decimal. 44%=.44

3.Square root .44 to find q. √.44=.66  (recessive allele)

4.Use the equation 1-q=p to determine p. 1-.66=.34  (dominant allele)

5.Multiply square .34 to find p2. p2=.11  (homozygous dominant individual)

6.Substitute p and q in the equation 2pq. 2(.34)(.66)=.45  (heterozygous individual)

7.Check answer by using p+q=1 and p2+q2+2pq=1. .34+.66=1  .11+.45+.44=1

8.Multiply all 3 genotypes by 1000 to find the number of individuals of each genotype.
44% x 1000 = 440  11% x 1000 = 110  45% x 1000 = 450

ANSWER
440 homozygous recessive individuals
110 homozygous dominant individuals
450 heterozygous individuals

*N.F. means the group wasn't done collecting data for Day 2

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